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JEE Main 2024 (9 Apr, Shift 2) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2024 (9 Apr, Shift 2)

Q18JEE Main 2024 · 9 APR · SHIFT 2Easy

Applications of Dimensional Analysis

The de-Broglie wavelength associated with a particle of mass mm and energy EE is h/2mEh/\sqrt{2mE}. The dimensional formula for Planck's constant is:

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Answer: (c)

  1. λ=h/2mE⇒h=λ2mE\lambda = h/\sqrt{2mE} \Rightarrow h = \lambda\sqrt{2mE}.
  2. mE\sqrt{mE} is momentum: [MLT−1][MLT^{-1}].
  3. [h]=[L][MLT−1]=[ML2T−1][h] = [L][MLT^{-1}] = [ML^2T^{-1}].
  4. So the answer is (c).
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