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NEET 2023 · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2023

Q66NEET 2023Easy

Matter Waves: de Broglie Wavelength

The de Broglie wavelength associated with an electron, accelerated by a potential difference of 81 V is given by:

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Answer: (d)

  1. For an electron, λ=1.227V\lambda = \dfrac{1.227}{\sqrt{V}} nm.
  2. λ=1.22781=1.2279≈0.136\lambda = \dfrac{1.227}{\sqrt{81}} = \dfrac{1.227}{9} \approx 0.136 nm.
  3. So the answer is (d) 0.136 nm.
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