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JEE Main 2021 (16 Mar, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2021 (16 Mar, Shift 2)

Q95JEE Main 2021 · 16 MAR · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through same potential of 100 V. What should nearly be the ratio of their wavelengths? (mp = 1.00727u me = 0.00055u)

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Answer: (d)

Same charge and same $V$ : $\dfrac{\lambda_e}{\lambda_p} = \sqrt{\dfrac{m_p}{m_e}}$ .
$\sqrt{\dfrac{1.00727}{0.00055}} = \sqrt{1831} \approx 42.8 \approx 43$
So the answer is (d) $43 : 1$ .

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