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MHT CET 2023 (14 May, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2023 (14 May, Shift 1)

Q62MHT CET 2023 · 14 MAY · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

The de-Broglie wavelength (λ)(\lambda) of a particle is related to its kinetic energy (E) as

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Answer: (d)

  1. p=2mEp = \sqrt{2mE}, so λ=h2mE\lambda = \dfrac{h}{\sqrt{2mE}}.
  2. Hence λ∝E−1/2\lambda \propto E^{-1/2}.
  3. So the answer is (d) λ∝E−12\lambda \propto E^{-\frac{1}{2}}.
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