The de-Broglie wavelength (λ) of a particle (a) is inversely proportional to impulse. (b) does not depend on impulse. (c) is proportional to mass. (d) is proportional to impulse.

Answer: (a). Impulse equals change in momentum; for a particle starting from rest, impulse = p. λ = h/p, so λ ∝ (1)/(impulse). So the answer is (a) inversely proportional to impulse.

The de-Broglie wavelength (λ) of a particle | MHT CET 2025 (21 Apr, Shift 1)

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Matter Waves: de Broglie Wavelength

The de-Broglie wavelength $(\lambda)$ of a particle

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Answer: (a)

Impulse equals change in momentum; for a particle starting from rest, impulse $= p$ .
$\lambda = \dfrac{h}{p}$ , so $\lambda \propto \dfrac{1}{\text{impulse}}$ .
So the answer is (a) inversely proportional to impulse.

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