The de-Broglie wavelength λ of a particle (a) is proportional to mass (b) is proportional to momentum (c) is inversely proportional to momentum (d) does not depend on momentum

Answer: (c). de Broglie relation: λ = h/p, so λ ∝ 1/p. So the answer is (c) inversely proportional to momentum.

The de-Broglie wavelength λ of a particle | MHT CET 2026 (14 May, Shift 1)

Q2MHT CET 2026 · 14 MAY · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

The de-Broglie wavelength $\lambda$ of a particle

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Answer: (c)

de Broglie relation: $\lambda = \dfrac{h}{p}$ , so $\lambda \propto \dfrac{1}{p}$ .
So the answer is (c) inversely proportional to momentum.

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