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MHT CET 2026 (19 May, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (19 May, Shift 1)

Q6MHT CET 2026 · 19 MAY · SHIFT 1Easy

Bohr Model: Orbits, Speed & Angular Momentum

The de Broglie wavelength of an electron moving in the nthn^{th} Bohr orbit of radius 'rr' is

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Answer: (c)

  1. Bohr condition: nn whole waves fit on the orbit, 2πr=nλ2\pi r = n\lambda.
  2. λ=2πrn\lambda = \frac{2\pi r}{n}
  3. So the answer is (c) 2πrn\frac{2\pi r}{n}.
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