Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Matter Waves: de Broglie Wavelength›Question 139

NEET 2013 · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2013

Q139NEET 2013Medium

Matter Waves: de Broglie Wavelength

The de-broglie wavelength of neutrons in thermal equilibrium at temperature T is

Show answer and solution

Answer: (d)

  1. λ=h2mK\lambda = \dfrac{h}{\sqrt{2mK}} with mn=1.675×10−27 kgm_n = 1.675 \times 10^{-27}\text{ kg}.
  2. Taking K≈kTK \approx kT: 2mnk=2×1.675×10−27×1.38×10−23≈2.15×10−25\sqrt{2m_nk} = \sqrt{2 \times 1.675 \times 10^{-27} \times 1.38 \times 10^{-23}} \approx 2.15 \times 10^{-25}
  3. λ=6.63×10−342.15×10−25T≈3.08×10−9T m=30.8T A˚\lambda = \dfrac{6.63 \times 10^{-34}}{2.15 \times 10^{-25}\sqrt{T}} \approx \dfrac{3.08 \times 10^{-9}}{\sqrt{T}}\text{ m} = \dfrac{30.8}{\sqrt{T}}\ \mathring{A}
  4. (With K=32kTK = \frac{3}{2}kT the value is 25.2/T25.2/\sqrt{T} Å, not listed, so the options use K=kTK = kT.)
  5. So the answer is (d) 30.8T A˚\frac{30.8}{\sqrt{T}}\ \mathring{A}.
Report a mistake

More questions on Matter Waves: de Broglie Wavelength