The de Broglie wavelength of the electron in the ground state is λ₁ and that in the n = 3 level is λ₃ then λ₃ is given by (a) (λ₁)/(3) (b) (λ₁)/(2) (c) 2λ₁ (d) 3λ₁

Answer: (d). λ = (2π r)/(n) with r ∝ n² gives λ ∝ n (also λ = h/mv, v ∝ 1/n). λ₃ = 3λ₁ So the answer is (d) 3λ₁.

The de Broglie wavelength of the electron in the ground state is λ₁… | MHT CET 2026 (18 Apr, Shift 2)

Q8MHT CET 2026 · 18 APR · SHIFT 2Easy

Bohr Model: Orbits, Speed & Angular Momentum

The de Broglie wavelength of the electron in the ground state is $\lambda_1$ and that in the $n = 3$ level is $\lambda_3$ then $\lambda_3$ is given by

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Answer: (d)

$\lambda = \frac{2\pi r}{n}$ with $r \propto n^2$ gives $\lambda \propto n$ (also $\lambda = \frac{h}{mv}$ , $v \propto \frac{1}{n}$ ).
$\lambda_3 = 3\lambda_1$
So the answer is (d) $3\lambda_1$ .

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Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (18 Apr, Shift 2)

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