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JEE Main 2022 (28 Jun, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2022 (28 Jun, Shift 1)

Q86JEE Main 2022 · 28 JUN · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

The de Broglie wavelengths for an electron and a photon are $\lambda$ e and $\lambda$ p respectively. For the same kinetic energy of electron and photon, which of the following presents the correct relation between the de Broglie wavelengths of two?

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Answer: (a)

Electron: $\lambda_e = \dfrac{h}{\sqrt{2mK}} \Rightarrow K = \dfrac{h^2}{2m\lambda_e^2}$ .
Photon with the same energy: $\lambda_p = \dfrac{hc}{K} = \dfrac{2mc}{h}\lambda_e^2$
So $\lambda_p \propto \lambda_e^2$ : the answer is (a).

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