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JEE Main 2024 (1 Feb, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2024 (1 Feb, Shift 1)

Q56JEE Main 2024 · 1 FEB · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

The de Broglie wavelengths of a proton and an α\alpha particle are λ\lambda and 2λ2\lambda respectively. The ratio of the velocities of proton and α\alpha particle will be:

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Answer: (a)

  1. λ=hmv⇒v=hmλ\lambda = \dfrac{h}{mv} \Rightarrow v = \dfrac{h}{m\lambda}.
  2. vpvα=mαλαmpλp=4mp⋅2λmp⋅λ=8\dfrac{v_p}{v_\alpha} = \dfrac{m_\alpha \lambda_\alpha}{m_p \lambda_p} = \dfrac{4m_p \cdot 2\lambda}{m_p \cdot \lambda} = 8
  3. So the answer is (a) 8:18 : 1.
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