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NEET 2010 (AIPMT, Mains) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2010 (AIPMT, Mains)

Q104NEET 2010 · AIPMT · MAINSMedium

Law of Radioactive Decay

The decay constant of a radio isotope is λ\lambda. If A1 and A2 are its activities at times t1 and t2 respectively, the number of nuclei which have decayed during the time (t1 −- t2)

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Answer: (c)

  1. A=λNA = \lambda N, so N1=A1λN_1 = \frac{A_1}{\lambda} and N2=A2λN_2 = \frac{A_2}{\lambda}.
  2. Nuclei decayed =N1−N2=A1−A2λ= N_1 - N_2 = \frac{A_1 - A_2}{\lambda}.
  3. So the answer is (c) (A1−A2)/λ(A_1 - A_2)/\lambda.
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