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NEET 2004 (AIPMT) · Acceleration Due to Gravity

Acceleration Due to Gravity question from NEET 2004 (AIPMT)

Q128NEET 2004 · AIPMTEasy

Acceleration Due to Gravity

The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be

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Answer: (d)

  1. g=43πGρRg = \frac{4}{3}\pi G\rho R, so equal gg needs equal ρR\rho R.
  2. 2ρ⋅Rp=ρR⇒Rp=R22\rho \cdot R_p = \rho R \Rightarrow R_p = \frac{R}{2}
  3. So the answer is (d) 12R\frac{1}{2}R.
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