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MHT CET 2021 (24 Sep, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2021 (24 Sep, Shift 2)

Q87MHT CET 2021 · 24 SEP · SHIFT 2Easy

Acceleration Due to Gravity

The depth from the surface of the earth of radius $R$ , at which acceleration due to gravity will be $60\%$ of the value on the earth surface is

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Answer: (b)

At depth $d$ : $g_d = g\left(1 - \frac{d}{R}\right)$ .
$0.6g = g\left(1 - \frac{d}{R}\right) \Rightarrow \frac{d}{R} = 0.4$
So the answer is (b) $d = \frac{2R}{5}$ .

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