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MHT CET 2026 (12 May, Shift 1) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2026 (12 May, Shift 1)

Q6MHT CET 2026 · 12 MAY · SHIFT 1Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

The difference between two molar specific heats of a gas is 70007000 J-kg−1-1-K −1-1. If the ratio of two specific heats of gas is 7/57/5, the molar specific heat of the gas at constant pressure in J-kg −1-1-K −1-1 is

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Answer: (c)

  1. Cp−Cv=7000C_p - C_v = 7000 and Cv=CpγC_v = \frac{C_p}{\gamma}.
  2. Cp(1−1γ)=7000⇒Cp=γγ−1×7000C_p\left(1 - \frac{1}{\gamma}\right) = 7000 \Rightarrow C_p = \frac{\gamma}{\gamma-1}\times 7000
  3. Cp=7/52/5×7000=3.5×7000=24500C_p = \frac{7/5}{2/5}\times 7000 = 3.5 \times 7000 = 24500
  4. So the answer is (c) 2450024500 J kg−1^{-1} K−1^{-1}.
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