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JEE Main 2022 (25 Jun, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from JEE Main 2022 (25 Jun, Shift 1)

Q49JEE Main 2022 · 25 JUN · SHIFT 1Medium

Refraction, Glass Slab & Apparent Depth

The difference of speed of light in the two media A and B (vA −- vB) is 2.6 ×\times 107 m/s. If the refractive index of medium B is 1.47, then the ratio of refractive index of medium B to medium A is: (Given: speed of light in vacuum c = 3 ×\times 108 ms−1{}^{-1})

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Answer: (c)

  1. vB=cμB=3×1081.47=2.041×108v_B = \dfrac{c}{\mu_B} = \dfrac{3 \times 10^8}{1.47} = 2.041 \times 10^8 m/s.
  2. vA=vB+0.26×108=2.301×108v_A = v_B + 0.26 \times 10^8 = 2.301 \times 10^8 m/s.
  3. μBμA=vAvB=2.3012.041≈1.13\dfrac{\mu_B}{\mu_A} = \dfrac{v_A}{v_B} = \dfrac{2.301}{2.041} \approx 1.13.
  4. So the answer is (c) 1.13.
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