The dimension of (B²)/(2μ₀), where B is magnetic field and μ₀ is the magnetic permeability of vacuum, is: (a) ML2T–2 (b) MLT–2 (c) ML-1T–2 (d) ML2T–1

Answer: (c). B²/(2μ₀) is the energy stored per unit volume in a magnetic field. [energy/volume] = ML²T⁻²/L³ = ML⁻¹T⁻² So the answer is (c).

The dimension of (B²)/(2μ₀), where B is magnetic field and μ₀ is the… | JEE Main 2020 (7 Jan, Shift 2)

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Units & Dimensions

The dimension of $\frac{B^2}{2\mu_0}$ , where B is magnetic field and $\mu_0$ is the magnetic permeability of vacuum, is:

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Answer: (c)

$B^2/(2\mu_0)$ is the energy stored per unit volume in a magnetic field.
$[\text{energy}/\text{volume}] = \mathrm{ML^2T^{-2}}/\mathrm{L^3} = \mathrm{ML^{-1}T^{-2}}$
So the answer is (c).