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JEE Main 2008 (AIEEE) · Units & Dimensions

Units & Dimensions question from JEE Main 2008 (AIEEE)

Q92JEE Main 2008 · AIEEEEasy

Units & Dimensions

The dimension of magnetic field in M, L, T and C (coulomb) is given as

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Answer: (c)

  1. Magnetic force F=qvBF = qvB, so B=F/(qv)B = F/(qv).
  2. [B]=MLT−2C⋅LT−1=MT−1C−1[B] = \frac{\mathrm{MLT^{-2}}}{\mathrm{C}\cdot\mathrm{LT^{-1}}} = \mathrm{MT^{-1}C^{-1}}
  3. So the answer is (c).
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