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JEE Main 2022 (26 Jun, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2022 (26 Jun, Shift 2)

Q49JEE Main 2022 · 26 JUN · SHIFT 2Easy

Units & Dimensions

The dimension of mutual inductance is:

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Answer: (c)

  1. M=Φ/IM = \Phi/I, and Φ=BA\Phi = BA with [B]=[F/(IL)]=MT−2A−1[B] = [F/(IL)] = \mathrm{MT^{-2}A^{-1}}.
  2. [Φ]=ML2T−2A−1[\Phi] = \mathrm{ML^2T^{-2}A^{-1}}
  3. [M]=ML2T−2A−2[M] = \mathrm{ML^2T^{-2}A^{-2}}
  4. So the answer is (c).
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