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NEET 1999 (AIPMT) · Units & Dimensions

Units & Dimensions question from NEET 1999 (AIPMT)

Q106NEET 1999 · AIPMTEasy

Units & Dimensions

The dimensional formula for magnetic flux is

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Answer: (a)

  1. ϕ=BA\phi = BA and F=BIl⇒[B]=[MLT−2][AL]=[MT−2A−1]F = BIl \Rightarrow [B] = \frac{[\mathrm{MLT^{-2}}]}{[\mathrm{AL}]} = [\mathrm{MT^{-2}A^{-1}}]
  2. [ϕ]=[MT−2A−1][L2]=[ML2T−2A−1][\phi] = [\mathrm{MT^{-2}A^{-1}}][\mathrm{L^2}] = [\mathrm{ML^2T^{-2}A^{-1}}]
  3. So the answer is (a).
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