The dimensional formula of permeability of free space μ₀ is (a) [MLT⁻²A⁻²] (b) [M⁰L¹T] (c) [M⁰L²T⁻¹A²] (d) none of these

Answer: (a). Force per length between two wires: F/l = (μ₀ I₁ I₂)/(2π d) ⇒ μ₀ = (2π F d)/(I₁ I₂ l) [μ₀] = [MLT⁻²][A²] = [MLT⁻²A⁻²] So the answer is (a).

The dimensional formula of permeability of free space μ₀ is | NEET 1991 (AIPMT)

Q114NEET 1991 · AIPMTEasy

Units & Dimensions

The dimensional formula of permeability of free space $\mu_0$ is

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Answer: (a)

Force per length between two wires: $\frac{F}{l} = \frac{\mu_0 I_1 I_2}{2\pi d} \Rightarrow \mu_0 = \frac{2\pi F d}{I_1 I_2 l}$
$[\mu_0] = \frac{[\mathrm{MLT^{-2}}]}{[\mathrm{A^2}]} = [\mathrm{MLT^{-2}A^{-2}}]$
So the answer is (a).

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