The dimensions [MLT ⁻²A⁻ 2] belong to the (a) Magnetic flux (b) Self inductance (c) Magnetic permeability (d) Electric permittivity

Answer: (c). F = (μ₀ I₁ I₂ l)/(2π d) ⇒ [μ₀] = [MLT⁻²][A²] [μ₀] = [MLT⁻²A⁻²] So the answer is (c) magnetic permeability.

The dimensions [MLT ⁻²A⁻ 2] belong to the | NEET 2022 (Phase 1)

Q46NEET 2022 · PHASE 1Easy

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The dimensions [MLT ${}^{-2}\mathrm{A}^{-}$ 2] belong to the

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Answer: (c)

$F = \frac{\mu_0 I_1 I_2 l}{2\pi d} \Rightarrow [\mu_0] = \frac{[\mathrm{MLT^{-2}}]}{[\mathrm{A^2}]}$
$[\mu_0] = [\mathrm{MLT^{-2}A^{-2}}]$
So the answer is (c) magnetic permeability.