The dimensions of Planck's constant equals to that of (a) energy (b) momentum (c) angular momentum (d) power

Answer: (c). E = hν ⇒ [h] = [ML²T⁻²][T⁻¹] = [ML²T⁻¹] Angular momentum L = mvr → [ML²T⁻¹] So the answer is (c) angular momentum.

The dimensions of Planck's constant equals to that of | NEET 2001 (AIPMT)

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Units & Dimensions

The dimensions of Planck's constant equals to that of

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Answer: (c)

$E = h\nu \Rightarrow [h] = \frac{[\mathrm{ML^2T^{-2}}]}{[\mathrm{T^{-1}}]} = [\mathrm{ML^2T^{-1}}]$
Angular momentum $L = mvr \to [\mathrm{ML^2T^{-1}}]$
So the answer is (c) angular momentum.