The dimensions of universal gravitational constant are (a) [M ⁻¹ L3T ⁻² ] (b) [ML2T ⁻¹ ] (c) [M ⁻² L3T ⁻² ] (d) [M ⁻² L2T ⁻¹ ]

Answer: (a). F = (Gm₁m₂)/(r²) ⇒ G = (Fr²)/(m₁m₂) [G] = [MLT⁻²][L²][M²] = [M⁻¹L³T⁻²] So the answer is (a).

The dimensions of universal gravitational constant are | NEET 2004 (AIPMT)

Q99NEET 2004 · AIPMTEasy

Units & Dimensions

The dimensions of universal gravitational constant are

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Answer: (a)

$F = \frac{Gm_1m_2}{r^2} \Rightarrow G = \frac{Fr^2}{m_1m_2}$
$[G] = \frac{[\mathrm{MLT^{-2}}][\mathrm{L^2}]}{[\mathrm{M^2}]} = [\mathrm{M^{-1}L^3T^{-2}}]$
So the answer is (a).