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NEET 1997 (AIPMT) · P-N Junction Diode

P-N Junction Diode question from NEET 1997 (AIPMT)

Q127NEET 1997 · AIPMTMedium

P-N Junction Diode

The diode used in the circuit shown in the figure has a constant voltage drop at 0.5 V0.5\text{ V} at all currents and a maximum power rating of 100 milli watts. What should be the value of the resistor RR, connected in series with diode for obtaining maximum current?

Figure

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Answer: (c)

  1. Maximum diode power P=VdIP = V_d I: Imax=100×10−30.5=0.2I_{max} = \dfrac{100\times 10^{-3}}{0.5} = 0.2 A
  2. Voltage across RR =1.5−0.5=1.0= 1.5 - 0.5 = 1.0 V
  3. R=1.00.2=5 ΩR = \dfrac{1.0}{0.2} = 5\ \Omega
  4. So the answer is (c) 5 Ω5\ \Omega.
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