Physics Circle home Student Login

Home›Chapters›Electromagnetic Waves PYQs›Displacement Current, Maxwell's Equations & Production›Question 11

JEE Main 2022 (29 Jun, Shift 2) · Displacement Current, Maxwell's Equations & Production

Displacement Current, Maxwell's Equations & Production question from JEE Main 2022 (29 Jun, Shift 2)

Q11JEE Main 2022 · 29 JUN · SHIFT 2Medium

Displacement Current, Maxwell's Equations & Production

The displacement current of 4.425 μ\muA is developed in the space between the plates of parallel plate capacitor when voltage is changing at a rate of 106 Vs−1{}^{-1}. The area of each plate of the capacitor is 40 cm2. The distance between each plate of the capacitor is x ×\times 10−-3 m. The value of x is __________.

(Permittivity of free space, ε0\varepsilon_0 = 8.85 ×\times 10−-12 C2 N−1{}^{-1} m−2{}^{-2}).

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 8

  1. Id=CdVdt=ε0AddVdt⇒d=ε0AIddVdtI_d = C\dfrac{dV}{dt} = \dfrac{\varepsilon_0 A}{d}\dfrac{dV}{dt} \Rightarrow d = \dfrac{\varepsilon_0 A}{I_d}\dfrac{dV}{dt}.
  2. d=8.85×10−12×40×10−4×1064.425×10−6=3.54×10−84.425×10−6d = \dfrac{8.85 \times 10^{-12} \times 40 \times 10^{-4} \times 10^{6}}{4.425 \times 10^{-6}} = \dfrac{3.54 \times 10^{-8}}{4.425 \times 10^{-6}}.
  3. d=8×10−3d = 8 \times 10^{-3} m.
  4. Answer: x=8x = 8.
Report a mistake

More questions on Displacement Current, Maxwell's Equations & Production