The displacement of a particle executing S.H.M. is x = asin (ω t - φ). Velocity of the particle at time t = (φ)/(ω) is (cos 0° = 1) (a) ωcos φ (b) aω (c) ωcos 2φ (d) -aωcos 2φ

Answer: (b). v = dx/dt = aωcos (ω t - φ) At t = (φ)/(ω): ω t - φ = 0, so v = aωcos 0° = aω So the answer is (b) aω.

The displacement of a particle executing S.H.M. is x = asin (ω t -… | MHT CET 2023 (14 May, Shift 1)

Q39MHT CET 2023 · 14 MAY · SHIFT 1Easy

Velocity & Acceleration in SHM

The displacement of a particle executing S.H.M. is $x = a\sin(\omega t - \phi)$ . Velocity of the particle at time $t = \frac{\phi}{\omega}$ is $(\cos 0^\circ = 1)$

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Answer: (b)

$v = \frac{dx}{dt} = a\omega\cos(\omega t - \phi)$
At $t = \frac{\phi}{\omega}$ : $\omega t - \phi = 0$ , so $v = a\omega\cos 0^\circ = a\omega$
So the answer is (b) $a\omega$ .

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