The displacement of an object attached to a spring and executing simple harmonic motion is given by x = 2 × 10⁻²cos π t metre. The time at which the maximum speed first occurs is (a) 0.25 s (b) 0.5 s (c) 0.75 s (d) 0.125 s

Answer: (b). ω = π, so T = (2π)/(π) = 2 s. x = Acos π t starts at the extreme position; maximum speed is at the mean position. First reached after T/4 = 0.5 s. So the answer is (b) 0.5 s.

The displacement of an object attached to a spring and executing… | JEE Main 2007 (AIEEE)

Q75JEE Main 2007 · AIEEEEasy

Periodic Motion & SHM Basics

The displacement of an object attached to a spring and executing simple harmonic motion is given by $x = 2 \times 10^{-2}\cos \pi t$ metre. The time at which the maximum speed first occurs is

Show answer and solution

Answer: (b)

$\omega = \pi$ , so $T = \frac{2\pi}{\pi} = 2\ \text{s}$ .
$x = A\cos\pi t$ starts at the extreme position; maximum speed is at the mean position.
First reached after $\frac{T}{4} = 0.5\ \text{s}$ .
So the answer is (b) 0.5 s.

Report a mistake

Periodic Motion & SHM Basics question from JEE Main 2007 (AIEEE)

More questions on Periodic Motion & SHM Basics