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JEE Main 2022 (27 Jun, Shift 1) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from JEE Main 2022 (27 Jun, Shift 1)

Q40JEE Main 2022 · 27 JUN · SHIFT 1Easy

Periodic Motion & SHM Basics

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is:

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Answer: (d)

From the mean position: $x = A\sin\frac{2\pi t}{T}$ .
$\frac{A}{2} = A\sin\frac{2\pi (3)}{T} \Rightarrow \frac{6\pi}{T} = \frac{\pi}{6}$ .
$T = 36\ \text{s}$ .
So the answer is (d) 36 s.

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