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JEE Main 2003 (AIEEE) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2003 (AIEEE)

Q100JEE Main 2003 · AIEEEEasy

Progressive Wave Equation

The displacement yy of a wave travelling in the xx-direction is given by

y=10−4sin⁡(600t−2x+π3) metresy = 10^{-4}\sin\left(600t - 2x + \frac{\pi}{3}\right)\text{ metres}

where xx is expressed in metres and tt in seconds. The speed of the wave - motion, in ms−1\text{ms}^{-1}, is

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Answer: (a)

  1. ω=600 rad/s\omega = 600\text{ rad/s}, k=2 m−1k = 2\text{ m}^{-1}
  2. v=ωk=6002=300 m/sv = \dfrac{\omega}{k} = \dfrac{600}{2} = 300\text{ m/s}
  3. So the answer is (a) 300300.
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