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JEE Main 2024 (30 Jan, Shift 1) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2024 (30 Jan, Shift 1)

Q42JEE Main 2024 · 30 JAN · SHIFT 1Easy

Spherical Surfaces & Thin Lenses

The distance between object and its two times magnified real image as produced by a convex lens is 45 cm45\text{ cm}. The focal length of the lens used is _______ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 10

  1. Real image, ∣m∣=2|m| = 2: v=2∣u∣v = 2|u| and ∣u∣+v=45|u| + v = 45 cm.
  2. 3∣u∣=45⇒∣u∣=15 cm3|u| = 45 \Rightarrow |u| = 15\text{ cm}, v=30 cmv = 30\text{ cm}
  3. 1f=130+115=330⇒f=10 cm\frac{1}{f} = \frac{1}{30} + \frac{1}{15} = \frac{3}{30} \Rightarrow f = 10\text{ cm}
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