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JEE Main 2023 (25 Jan, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2023 (25 Jan, Shift 1)

Q57JEE Main 2023 · 25 JAN · SHIFT 1Easy

Progressive Wave Equation

The distance between two consecutive points with phase difference of 60∘^\circ in a wave of frequency 500 Hz is 6.0 m. The velocity with which wave is travelling is __________ km/s

Numerical answer type. Work it out, then open the answer.

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Answer: 18

  1. Δx=λ2πΔϕ\Delta x = \frac{\lambda}{2\pi}\Delta\phi with Δϕ=π3\Delta\phi = \frac{\pi}{3} gives Δx=λ6\Delta x = \frac{\lambda}{6}
  2. λ6=6.0 m⇒λ=36 m\frac{\lambda}{6} = 6.0\text{ m} \Rightarrow \lambda = 36\text{ m}
  3. v=fλ=500×36=18000 m/sv = f\lambda = 500 \times 36 = 18000\text{ m/s}
  4. So v=18 km/sv = 18\text{ km/s}.
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