The distance between two consecutive points with phase difference of 60° in wave of frequency 500 Hz is 0.6 m. The velocity with which wave is travelling is (a) 1.8 km/s (b) 9 km/s (c) 3.6 km/s (d) 2.7 km/s

Answer: (a). 60° phase difference means Δ x = (λ)/(6), so λ = 6 × 0.6 = 3.6 m. v = fλ = 500 × 3.6 = 1800 m/s So the answer is (a) 1.8 km/s.

The distance between two consecutive points with phase difference of… | MHT CET 2024 (4 May, Shift 1)

Q42MHT CET 2024 · 4 MAY · SHIFT 1Easy

Progressive Wave Equation

The distance between two consecutive points with phase difference of $60^\circ$ in wave of frequency 500 Hz is 0.6 m. The velocity with which wave is travelling is

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Answer: (a)

$60^\circ$ phase difference means $\Delta x = \frac{\lambda}{6}$ , so $\lambda = 6 \times 0.6 = 3.6$ m.
$v = f\lambda = 500 \times 3.6 = 1800$ m/s
So the answer is (a) $1.8$ km/s.

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