The distance between two consecutive points with phase difference of 60° in a wave of frequency n is x meter. The velocity with which wave is traveling is (a) nx (b) 2nx (c) 3nx (d) 6nx

Answer: (d). 60° = π/3 corresponds to Δ x = (λ)/(6), so x = (λ)/(6) and λ = 6x. v = nλ = 6nx So the answer is (d) 6nx.

The distance between two consecutive points with phase difference of… | MHT CET 2026 (13 Apr, Shift 2)

Q20MHT CET 2026 · 13 APR · SHIFT 2Easy

Progressive Wave Equation

The distance between two consecutive points with phase difference of $60^\circ$ in a wave of frequency $n$ is $x$ meter. The velocity with which wave is traveling is

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Answer: (d)

$60^\circ = \frac{\pi}{3}$ corresponds to $\Delta x = \frac{\lambda}{6}$ , so $x = \frac{\lambda}{6}$ and $\lambda = 6x$ .
$v = n\lambda = 6nx$
So the answer is (d) $6nx$ .

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