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JEE Main 2023 (25 Jan, Shift 2) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from JEE Main 2023 (25 Jan, Shift 2)

Q20JEE Main 2023 · 25 JAN · SHIFT 2Easy

Velocity, Acceleration & Variable Motion

The distance travelled by a particle is related to time t as x=4t2x = 4t^2. The velocity of the particle at t=5s is :-

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Answer: (d)

  1. v=dxdt=8tv = \frac{dx}{dt} = 8t
  2. At t=5t = 5 s: v=40v = 40 m/s
  3. So the answer is (d) 40 ms−140\text{ ms}^{-1}.
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