The distance travelled by a particle starting from rest and moving with an acceleration 4/3 m s ⁻², in the third second is (a) 10/3 m (b) 19/3 m (c) 6 m (d) 4 m

Answer: (a). Distance in the n th second: Sn = u + a/2(2n - 1), with u = 0. S₃ = 1/2 × 4/3 × (2 × 3 - 1) = 2/3 × 5 S₃ = 10/3 m So the answer is (a) 10/3 m.

The distance travelled by a particle starting from rest and moving… | NEET 2008 (AIPMT)

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Equations of Kinematics

The distance travelled by a particle starting from rest and moving with an acceleration $\frac{4}{3}$ m s ${}^{-2}$ , in the third second is

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Answer: (a)

Distance in the $n$ th second: $S_n = u + \frac{a}{2}(2n - 1)$ , with $u = 0$ .
$S_3 = \frac{1}{2} \times \frac{4}{3} \times (2 \times 3 - 1) = \frac{2}{3} \times 5$
$S_3 = \frac{10}{3}\text{ m}$
So the answer is (a) $\frac{10}{3}$ m.

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