The efficiency of a Carnot engine operating with reservoir temperature of 100 and -23 will be (a) (373 + 250)/(373) (b) (373 - 250)/(373) (c) (100 + 23)/(100) (d) (100 - 23)/(100)

Answer: (b). T₁ = 100 + 273 = 373 K, T₂ = -23 + 273 = 250 K η = (T₁ - T₂)/(T₁) = (373 - 250)/(373) So the answer is (b).

The efficiency of a Carnot engine operating with reservoir… | NEET 1997 (AIPMT)

Q94NEET 1997 · AIPMTEasy

Heat Engines, Refrigerators & Second Law

The efficiency of a Carnot engine operating with reservoir temperature of $100^\circ\text{C}$ and $-23^\circ\text{C}$ will be

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Answer: (b)

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