Student Login

Home›Chapters›Thermodynamics PYQs›Heat Engines, Refrigerators & Second Law›Question 29

MHT CET 2023 (14 May, Shift 1) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from MHT CET 2023 (14 May, Shift 1)

Q29MHT CET 2023 · 14 MAY · SHIFT 1Medium

Heat Engines, Refrigerators & Second Law

The efficiency of a heat engine is ' $\eta$ ' and the coefficient of performance of a refrigerator is ' $\beta$ '. Then

Show answer and solution

Answer: (b)

$\eta = \frac{W}{Q_1}$ and $\beta = \frac{Q_2}{W} = \frac{Q_1 - W}{W} = \frac{1}{\eta} - 1$ .
$\beta + 1 = \frac{1}{\eta} \Rightarrow \eta = \frac{1}{\beta + 1}$
So the answer is (b) $\eta = \frac{1}{\beta+1}$ .

Report a mistake

More questions on Heat Engines, Refrigerators & Second Law

A Carnot engine is operating between the two reservoirs of temperature 227 and 127…JEE Main 2022 (30 Jul, Shift 2)
The efficiency of a Carnot's engine, working between steam point and ice point, will be:JEE Main 2022 (26 Jun, Shift 1)
A Carnot engine has efficiency of 50%. If the temperature of sink is reduced by 40, its…JEE Main 2022 (28 Jul, Shift 1)
In 1 st case, Carnot engine operates between temperatures 300 K and 100 K. In 2 nd case…JEE Main 2022 (27 Jul, Shift 2)
Let η₁ is the efficiency of an engine at T₁ = 447 and T₂ = 147 while η₂ is the efficiency…JEE Main 2022 (25 Jul, Shift 2)
A Carnot engine takes 5000 kcal of heat from a reservoir at 727 ° C and gives heat to a…JEE Main 2022 (24 Jun, Shift 2)
A Carnot engine whose heat sink is at 27 ° C, has an efficiency of 25%. By how many…JEE Main 2022 (24 Jun, Shift 1)
300 cal. of heat is given to a heat engine and it rejects 225 cal. If source temperature…JEE Main 2022 (29 Jun, Shift 1)