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NEET 2018 · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2018

Q61NEET 2018Easy

Heat Engines, Refrigerators & Second Law

The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is

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Answer: (a)

  1. T1=373T_1 = 373 K, T2=273T_2 = 273 K
  2. η=1−273373=100373=0.268\eta = 1 - \frac{273}{373} = \frac{100}{373} = 0.268
  3. So the answer is (a) 26.8%.
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