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NEET 2002 (AIPMT) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2002 (AIPMT)

Q91NEET 2002 · AIPMTMedium

Heat Engines, Refrigerators & Second Law

The efficiency of Carnot engine is 50% and temperature of sink is 500 K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of sink will be

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Answer: (c)

$T_1 = \frac{T_2}{1 - \eta} = \frac{500}{0.5} = 1000\text{ K}$
For $\eta = 0.6$ : $T_2' = (1 - 0.6)(1000) = 400\text{ K}$
So the answer is (c) 400 K.

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