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MHT CET 2026 (20 Apr, Shift 2) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from MHT CET 2026 (20 Apr, Shift 2)

Q3MHT CET 2026 · 20 APR · SHIFT 2Easy

Heat Engines, Refrigerators & Second Law

The efficiency of Carnot engine which operates between the two temperatures T1=500T_1 = 500 K and T2=300T_2 = 300 K is

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Answer: (d)

  1. η=1−T2T1=1−300500=0.4\eta = 1 - \frac{T_2}{T_1} = 1 - \frac{300}{500} = 0.4
  2. So the answer is (d) 40%40\%.
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