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JEE Main 2022 (25 Jul, Shift 2) · Biot-Savart Law & Circular Coils

Biot-Savart Law & Circular Coils question from JEE Main 2022 (25 Jul, Shift 2)

Q71JEE Main 2022 · 25 JUL · SHIFT 2Medium

Biot-Savart Law & Circular Coils

The electric current in a circular coil of 2 turns produces a magnetic induction B1 at its centre. The coil is unwound and is rewound into a circular coil of 5 turns and the same current produces a magnetic induction B2 at its centre. The ratio of $\frac{B_2}{B_1}$ is

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Answer: (b)

For the same wire, $B \propto n^2$ .
$\frac{B_2}{B_1} = \left(\frac{5}{2}\right)^2 = \frac{25}{4}$
So the answer is (b) $\frac{25}{4}$ .

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