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JEE Main 2026 (28 Jan, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from JEE Main 2026 (28 Jan, Shift 1)

Q8JEE Main 2026 · 28 JAN · SHIFT 1Difficult

AC Basics: Peak, RMS & Average Values

The electric current in the circuit is given as i=io(t/T)i = i_o (t/T). The r.m.s current for the period t=0t = 0 to t=Tt = T is ______.

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Answer: (b)

  1. irms2=1T∫0Ti2 dt=1T∫0Tio2t2T2 dti_{rms}^2 = \frac{1}{T}\int_0^T i^2\,dt = \frac{1}{T}\int_0^T \frac{i_o^2 t^2}{T^2}\,dt
  2. =io2T3⋅T33=io23= \frac{i_o^2}{T^3}\cdot\frac{T^3}{3} = \frac{i_o^2}{3}
  3. irms=io3i_{rms} = \frac{i_o}{\sqrt{3}}
  4. So the answer is (b).
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