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JEE Main 2024 (29 Jan, Shift 1) · Electric Current, Drift Velocity & Current Density

Electric Current, Drift Velocity & Current Density question from JEE Main 2024 (29 Jan, Shift 1)

Q5JEE Main 2024 · 29 JAN · SHIFT 1Easy

Electric Current, Drift Velocity & Current Density

The electric current through a wire varies with time as I=I0+βtI = I_0 + \beta t, where I0=20 AI_0 = 20\text{ A} and β=3 A/s\beta = 3\text{ A/s}. The amount of electric charge crossed through a section of the wire in 20 s20\text{ s} is:

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Answer: (c)

  1. q=∫020(I0+βt) dt=I0t+βt22q = \int_0^{20} (I_0 + \beta t)\,dt = I_0 t + \dfrac{\beta t^{2}}{2}
  2. q=20×20+3×4002=400+600q = 20 \times 20 + \dfrac{3 \times 400}{2} = 400 + 600
  3. q=1000 Cq = 1000\text{ C}
  4. So the answer is (c) 1000 C.
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