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JEE Main 2023 (24 Jan, Shift 2) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from JEE Main 2023 (24 Jan, Shift 2)

Q27JEE Main 2023 · 24 JAN · SHIFT 2Easy

Nature of EM Waves & Wave Equation

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

Ex=E0sin⁡(kz−ωt)E_x = E_0\sin(kz - \omega t)

By=B0sin⁡(kz−ωt)B_y = B_0\sin(kz - \omega t)

Then the correct relation between E0{}_0 and B0{}_0 is given by

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Answer: (c)

  1. Wave speed c=ωkc = \frac{\omega}{k} and E0=cB0E_0 = cB_0.
  2. E0=ωkB0⇒kE0=ωB0E_0 = \frac{\omega}{k}B_0 \Rightarrow kE_0 = \omega B_0.
  3. So the answer is (c).
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