The electric field at a point on the equatorial plane at a distance r from the centre of a dipole having dipole moment p is given by, ( r separation of two charges forming the dipole, ε₀ - permittivity of free space) (a) E = -(P)/(4πε₀ r³) (b) E = (P)/(4πε₀ r³) (c) E = (2P)/(4πε₀ r³) (d) E = -(P)/(4πε₀ r²)

Answer: (a). On the equatorial line the field has magnitude (p)/(4πε₀ r³). Its direction is opposite to p (from +q side to -q side, parallel to the axis). E = -(p)/(4πε₀ r³), answer (a).

The electric field at a point on the equatorial plane at a distance r… | NEET 2020 (Phase 2)

Q57NEET 2020 · PHASE 2Easy

Electric Dipole

The electric field at a point on the equatorial plane at a distance $r$ from the centre of a dipole having dipole moment $\vec{p}$ is given by,

( $r \gg$ separation of two charges forming the dipole, $\varepsilon_0$ - permittivity of free space)

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Answer: (a)

On the equatorial line the field has magnitude $\frac{p}{4\pi\varepsilon_0 r^3}$ .
Its direction is opposite to $\vec{p}$ (from $+q$ side to $-q$ side, parallel to the axis).
$\vec{E} = -\frac{\vec{p}}{4\pi\varepsilon_0 r^3}$ , answer (a).

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