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JEE Main 2024 (5 Apr, Shift 2) · Electric Dipole

Electric Dipole question from JEE Main 2024 (5 Apr, Shift 2)

Q34JEE Main 2024 · 5 APR · SHIFT 2Medium

Electric Dipole

The electric field at point PP due to an electric dipole is EE. The electric field at point RR on equatorial line will be Ex\frac{E}{x}. The value of xx:

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 16

  1. P is on the axis at distance rr: E=2kpr3E = \frac{2kp}{r^3}.
  2. R is on the equatorial line at 2r2r: ER=kp(2r)3=kp8r3E_R = \frac{kp}{(2r)^3} = \frac{kp}{8r^3}.
  3. ER=116⋅2kpr3=E16E_R = \frac{1}{16}\cdot\frac{2kp}{r^3} = \frac{E}{16}
  4. So x=16x = 16.
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