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MHT CET 2026 (16 Apr, Shift 1) · Energy Stored & Force between Plates

Energy Stored & Force between Plates question from MHT CET 2026 (16 Apr, Shift 1)

Q4MHT CET 2026 · 16 APR · SHIFT 1Easy

Energy Stored & Force between Plates

The electric field between the plates of a parallel plate capacitor is 'E'. If the charge on the plates is Q then the force on each plate is

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Answer: (c)

  1. Total field between plates E=σε0E = \frac{\sigma}{\varepsilon_0}; half of it, E2\frac{E}{2}, is due to each plate.
  2. A plate cannot push itself, so it feels only the other plate's field E2\frac{E}{2}.
  3. F=Q⋅E2F = Q \cdot \frac{E}{2}
  4. So the answer is (c) QE2\frac{QE}{2}.
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