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MHT CET 2026 (14 May, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2026 (14 May, Shift 2)

Q9MHT CET 2026 · 14 MAY · SHIFT 2Easy

Electric Flux & Gauss's Law

The electric field intensity at a point near and outside the surface of a charged conductor of any shape is $E_1$ . The electric field intensity due to a uniformly charged infinite thin plane sheet having the same surface charge density is $E_2$ . The relation between $E_1$ and $E_2$ is

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Answer: (c)

Just outside a charged conductor: $E_1 = \frac{\sigma}{\varepsilon_0}$ .
Infinite thin sheet (field on both sides): $E_2 = \frac{\sigma}{2\varepsilon_0}$ .
So $E_1 = 2E_2$ , answer (c).

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