The electric field of a plane electromagnetic wave is given by E = E₀(x + y)sin (kz - ω t) Its magnetic field will be given by: (a) E₀/c(x + y)sin (kz - ω t) (b) E₀/c(x - y)sin (kz - ω t) (c) E₀/c(x - y)cos (kz - ω t) (d) E₀/c(-x + y)sin (kz - ω t)

Answer: (d). sin (kz - ω t): wave along +z; B = ( k× E)/(c). k×( x + y) = y - x So the answer is (d) E₀/c(- x + y)sin (kz - ω t).

The electric field of a plane electromagnetic wave is given by E =… | JEE Main 2020 (4 Sep, Shift 2)

Q52JEE Main 2020 · 4 SEP · SHIFT 2Medium

Nature of EM Waves & Wave Equation

The electric field of a plane electromagnetic wave is given by

$\vec{E} = E_0\left(\hat{x} + \hat{y}\right)\sin(kz - \omega t)$

Its magnetic field will be given by:

Show answer and solution

Answer: (d)

$\sin(kz - \omega t)$ : wave along $+z$ ; $\vec B = \dfrac{\hat k\times\vec E}{c}$ .
$\hat k\times(\hat x + \hat y) = \hat y - \hat x$
So the answer is (d) $\dfrac{E_0}{c}(-\hat x + \hat y)\sin(kz - \omega t)$ .

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